← 📐 Mathematics

Cambridge IGCSE 0580 · Topic 4 of 10

Coordinate geometry, graphs and functions

Straight-line graphs, gradients, midpoints and lengths, the shapes of curves, functions, and differentiation.

📌 Key points

  1. Gradient = change in ychange in x = y₂ − y₁x₂ − x₁. Lines going up from left to right have positive gradients; lines going down have negative gradients.
  2. In y = mx + c, m is the gradient and c is the y-intercept. To find a line’s equation, find m first, then substitute a point to find c.
  3. Parallel lines have equal gradients. If two lines are perpendicular, their gradients multiply to −1, e.g. 2 and −12.
  4. The midpoint of (x₁, y₁) and (x₂, y₂) is (x₁ + x₂2, y₁ + y₂2); the length between them is √((x₂ − x₁)2 + (y₂ − y₁)2).
  5. Graph shapes: y = ax2 + bx + c is a parabola; y = x3 is a cubic; y = kx is a reciprocal graph with the axes as asymptotes; y = ax is exponential and passes through (0, 1).
  6. Solve equations graphically by reading the x-coordinates where two graphs intersect; the roots of f(x) = 0 are where y = f(x) crosses the x-axis.
  7. Functions: fg(x) means do g first, then f. The inverse f−1(x) undoes f: write y = f(x), swap x and y, and rearrange for y.
  8. The gradient of a curve at a point is the gradient of the tangent there. On a distance–time graph the gradient is speed; on a speed–time graph it is acceleration and the area underneath is distance.
  9. Differentiation: if y = axn then dydx = naxn−1. At a turning point dydx = 0.
  10. Inequalities on a graph: use a broken line for a strict inequality and a solid line for ≤ or ≥, then shade as the question instructs.

📖 Key terms

Gradient
The steepness of a line: change in y ÷ change in x.
y-intercept
Where a graph crosses the y-axis (x = 0).
Perpendicular
At right angles (90°) to each other.
Asymptote
A line that a curve gets closer and closer to but never meets.
Composite function
One function applied after another, e.g. fg(x) = f(g(x)).
Inverse function
The function that reverses f, written f−1(x).
Tangent
A straight line that touches a curve at one point.
Turning point
A point where the gradient is zero (a maximum or a minimum).

✏️ Worked example

A is (2, 1) and B is (6, 9). Find the equation of line AB, and of the line through A perpendicular to AB.

  1. Gradient of AB = 9 − 16 − 2 = 84 = 2.
  2. y = 2x + c through (2, 1): 1 = 4 + c, so c = −3 and AB is y = 2x − 3.
  3. The perpendicular gradient is −12, because 2 × (−12) = −1.
  4. y = −12x + c through (2, 1): 1 = −1 + c, so c = 2.
  5. Answer: AB is y = 2x − 3; the perpendicular line is y = −12x + 2.
💡 Exam tip

When finding a gradient from a graph, use two points far apart on the line and check the sign: a line sloping downwards must have a negative gradient.

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