← 📐 Mathematics

Cambridge IGCSE 0580 · Topic 3 of 10

Algebra: expressions, equations and sequences

Expanding and factorising, solving linear, simultaneous and quadratic equations, inequalities, rearranging formulae and nth terms.

📌 Key points

  1. Expand brackets by multiplying every term inside by the term outside. For two brackets multiply each term by each term: (x + 3)(x − 5) = x2 − 2x − 15.
  2. Factorise by taking out the HCF, e.g. 6x2 + 9x = 3x(2x + 3). Difference of two squares: a2 − b2 = (a + b)(a − b).
  3. To factorise x2 + bx + c, find two numbers that multiply to c and add to b: x2 + x − 12 = (x + 4)(x − 3).
  4. Solve equations by doing the same operation to both sides. With an inequality, reverse the sign when multiplying or dividing by a negative number.
  5. To change the subject of a formula, use inverse operations; if the new subject appears twice, collect those terms on one side and factorise.
  6. Simultaneous equations: make the coefficients of one letter the same, then add or subtract to eliminate it (or substitute). Check in the other equation.
  7. Quadratic equations: rearrange to = 0, then factorise, complete the square, or use x = −b ± √(b2 − 4ac)2a.
  8. Completing the square: x2 + 6x + 2 = (x + 3)2 − 9 + 2 = (x + 3)2 − 7.
  9. Algebraic fractions: factorise first, then cancel common factors; to add or subtract, use a common denominator.
  10. A linear sequence with common difference d has nth term dn + (first term − d). A quadratic sequence has a constant second difference.

📖 Key terms

Expression
A collection of terms with no equals sign, e.g. 3x + 2.
Equation
A statement that two expressions are equal, which can be solved.
Formula
A rule connecting two or more variables, e.g. A = πr2.
Subject
The variable on its own on one side of a formula.
Factorise
Write an expression as a product of factors (put into brackets).
Coefficient
The number in front of a letter, e.g. 5 in 5x.
nth term
A formula that gives any term of a sequence from its position n.

✏️ Worked example

Solve x2 − 4x − 7 = 0, giving your answers correct to 2 decimal places.

  1. It does not factorise, so use the formula with a = 1, b = −4, c = −7.
  2. b2 − 4ac = (−4)2 − 4 × 1 × (−7) = 16 + 28 = 44.
  3. x = 4 ± √442.
  4. x = 4 + 6.6332 = 5.316… or x = 4 − 6.6332 = −1.316…
  5. Answer: x = 5.32 or x = −1.32.
💡 Exam tip

“Give your answers to 2 decimal places” is a hint that the quadratic does not factorise: use the formula and write down the substitution to earn the method marks.

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