← ⚛️ Physics

Cambridge IGCSE 0625 · Topic 1 of 10

Measurement and motion

Measuring lengths and times, scalars and vectors, speed, velocity and acceleration, and motion graphs.

📌 Key points

  1. To measure something small (a thin sheet, a short time), measure many of them and divide, e.g. time 20 swings of a pendulum and divide by 20.
  2. Scalars have size only (distance, speed, time, mass, energy, temperature). Vectors have size and direction (force, weight, velocity, acceleration, momentum).
  3. Speed = distancetime; average speed = total distancetotal time. Velocity is speed in a given direction.
  4. Acceleration = change in velocitytime taken, a = ΔvΔt, in m/s2. A negative acceleration is a deceleration.
  5. On a distance–time graph the gradient is the speed; a horizontal line means the object is stationary.
  6. On a speed–time graph the gradient is the acceleration and the area under the graph is the distance travelled.
  7. Near the Earth’s surface, the acceleration of free fall g is approximately constant at 9.8 m/s2 (with no air resistance).
  8. A falling object speeds up until air resistance equals its weight; the resultant force is then zero and it falls at terminal velocity.
  9. Two perpendicular vectors combine by Pythagoras: 6 N east and 8 N north give a resultant of 10 N.

📖 Key terms

Scalar
A quantity with magnitude (size) only.
Vector
A quantity with magnitude and direction.
Speed
Distance travelled per unit time.
Velocity
Speed in a given direction (change in displacement per unit time).
Acceleration
Change in velocity per unit time.
Terminal velocity
The constant velocity reached when the drag force equals the weight.
Resultant
The single vector that has the same effect as two or more vectors together.

✏️ Worked example

A car accelerates uniformly from rest to 24 m/s in 8.0 s, then travels at 24 m/s for 10 s. Find its acceleration and the total distance travelled.

  1. Acceleration = ΔvΔt = 24 − 08.0 = 3.0 m/s2.
  2. Distance while accelerating = area of triangle = 12 × 8.0 × 24 = 96 m.
  3. Distance at constant speed = area of rectangle = 24 × 10 = 240 m.
  4. Answer: a = 3.0 m/s2 and total distance = 96 + 240 = 336 m.
💡 Exam tip

Check the axes before you start: on a distance–time graph the gradient is speed, but on a speed–time graph the gradient is acceleration and the area is distance.

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